{"id":16982,"date":"2023-05-30T09:20:14","date_gmt":"2023-05-30T06:20:14","guid":{"rendered":"https:\/\/starlanguageblog.com\/?p=16982"},"modified":"2023-05-30T09:20:14","modified_gmt":"2023-05-30T06:20:14","slug":"solving-power-equations","status":"publish","type":"post","link":"https:\/\/www.starlanguageblog.com\/solving-power-equations\/","title":{"rendered":"Solving Power Equations"},"content":{"rendered":"<h1><span style=\"font-weight: 400;\">Solving Power Equations<\/span><\/h1>\n<p><span style=\"font-weight: 400;\">We must separate the exponentiating variable to solve exponential functions. With &#8220;a&#8221; as the base and &#8220;x&#8221; as the exponent, exponential functions have the general form f(x) = axe. The objective is to identify the value of &#8220;x&#8221; that resolves the inequality or equation. There are various options depending on the precise issue and the desired resolution.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">We can frequently utilize logarithms to remove the variable from the exponent while solving power equations. We can simplify the equation and immediately solve for the variable by taking the logarithm of both sides of the equation. The exact challenge at hand, as well as any existing constraints, will determine the logarithm basis to use.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Let&#8217;s use the equation 2 x 16 as an example. By taking the logarithm of both sides and using a logarithm base to solve for &#8220;x,&#8221; we may make the problem simpler. Since the exponential function&#8217;s base is two, we can utilize the logarithm base 2 in this situation. Logarithmically speaking, log2(2x) = log2(16).<\/span><\/p>\n<p><span style=\"font-weight: 400;\">We reduce the equation to x = log2(16) using the logarithm property that says loga(ab) = b. x = 4 is the result of evaluating the right-hand side of the logarithm. Consequently, x = 4 is the equation 2x = 16&#8217;s answer.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The strategy is similar when dealing with inequalities using exponential functions. We can utilize logarithms to remove the variable from the exponent and directly answer the inequality. It&#8217;s crucial to remember that only when the base of the logarithm is positive do logarithms maintain the inequality&#8217;s order.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">It is essential to look for any constraints on the function&#8217;s domain or any potential superfluous solutions that might emerge throughout the solving process while solving exponential functions. Furthermore, the solutions could not be limited to real numbers if the function involved complex numbers.<\/span><\/p>\n<h2><span style=\"font-weight: 400;\">What Are Power Equations?<img fetchpriority=\"high\" decoding=\"async\" class=\"alignnone size-full wp-image-17289\" src=\"https:\/\/wordpress-1162154-4054340.cloudwaysapps.com\/wp-content\/uploads\/2023\/05\/pexels-katerina-holmes-5905715-1.webp\" alt=\"What Are Power Equations?\" width=\"640\" height=\"350\" \/><\/span><\/h2>\n<p><span style=\"font-weight: 400;\">An exponential equation is an equation with exponents where the exponent (or a part of the exponent) is a variable. For example, 3x = 81, 5x &#8211; 3 = 625, 62y &#8211; 7 = 121, etc. are some examples of power equations. We may come across the use of power equations when we are solving the problems of algebra, compound interest, exponential growth, exponential decay, etc.<\/span><\/p>\n<h3><b>Types of power equations<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">There are three types of power equations. They are as follows:<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Equations with the same bases on both sides. (Example: 4x = 42)<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Equations with different bases can be made the same. (Example: 4x = 16 which can be written as 4x = 42)<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Equations with different bases cannot be made the same. (Example: 4x = 15)<\/span><\/li>\n<\/ul>\n<h2><span style=\"font-weight: 400;\">Equations With Exponents<\/span><\/h2>\n<p><span style=\"font-weight: 400;\">We will go into the subject of equations with exponents, investigating their characteristics, norms, and solution methods.<\/span><\/p>\n<h3><b>Recognizing\u00a0Exponents\u00a0<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">Exponents are a quick way to represent repeated multiplication. They are also referred to as powers or indexes. An exponent indicates how many times a base has been multiplied by itself. For instance, the base and exponent in the expression 23 are 2 and 3, respectively. It denotes a three-fold multiplication of 2 by itself:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">2^3 = 2 \u00d7 2 \u00d7 2 = 8<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Exponents&#8217; characteristics make calculations simpler. One important characteristic is the product of powers, which causes the exponents to be added when two integers with the same base but different exponents are multiplied.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">a(m+n) = a(m a)<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The power of a power is another characteristic, according to which increasing one exponent by another exponent multiplies the exponents:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">(a m ) n = a m n<\/span><\/p>\n<p><span style=\"font-weight: 400;\">An understanding of these properties is necessary for manipulating and resolving equations with exponents.<\/span><\/p>\n<h3><b>Exponentiation of Equations<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">We must use techniques that decompose the equation and isolate the variable to solve equations with exponents. Here are several methods that are frequently used:<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\"><strong>Simplify both sides:<\/strong> Begin by separating the two sides of the equation. Combining similar terms and applying exponent rules can simplify expressions.<\/span><\/li>\n<\/ul>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\"><strong>Remove the exponent:<\/strong> Remove the exponent using inverse procedures. Take the square root of both sides to remove the exponent, like when the variable is increased to the power of 2.<\/span><\/li>\n<\/ul>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Applying logarithms can sometimes help resolve equations involving exponents. Since logarithms are exponentiation&#8217;s inverse operations, they can isolate the variable. Use logarithms with the same base as the exponent on both sides of the equation.<\/span><\/li>\n<\/ul>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\"><strong>Factorization:<\/strong> Remove the common base from the equation if any terms have the same base but distinct exponents. You can then solve for the variable and simplify the equation.<\/span><\/li>\n<\/ul>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Substitution: In some cases, replacing the exponentiated variable with a different one can simplify the equation. This method introduces a new variable to represent the original variable multiplied by a specific power.<\/span><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">You can solve for the variable and locate the solution to equations with exponents by using these methods and carefully altering the equation.<\/span><\/p>\n<h2><span style=\"font-weight: 400;\">Power Equations Formulas<img decoding=\"async\" class=\"alignnone size-full wp-image-17290\" src=\"https:\/\/wordpress-1162154-4054340.cloudwaysapps.com\/wp-content\/uploads\/2023\/05\/pexels-monstera-6238297-1-1.webp\" alt=\"Power Equations Formulas\" width=\"640\" height=\"350\" \/><\/span><\/h2>\n<p><span style=\"font-weight: 400;\">While solving an exponential equation, the bases on both sides may be the same or not. Here are the formulas used in each case, which we will learn in detail in the upcoming sections.<\/span><\/p>\n<h3><b>Property of Equality for power equations<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">This property is useful for solving an exponential equation with the same bases. It says that when the bases on both sides of an exponential equation are equal, the exponents must also be equal. i.e.,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">ax = ay \u21d4 x = y.<\/span><\/p>\n<h3><b>power equations to Logarithmic Form<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">We know that logarithms are nothing but exponents and vice versa. Hence, an exponential equation can be converted into a logarithmic function. This helps in the process of solving an exponential equation with different bases. Here is the formula to convert power equations into logarithmic equations.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">bx = a \u21d4 logba = x<\/span><\/p>\n<h2><span style=\"font-weight: 400;\">Solving Power Equations With The Same Bases<img decoding=\"async\" class=\"alignnone size-full wp-image-17291\" src=\"https:\/\/wordpress-1162154-4054340.cloudwaysapps.com\/wp-content\/uploads\/2023\/05\/pexels-cottonbro-studio-5184961.webp\" alt=\"Solving Power Equations With The Same Bases\" width=\"640\" height=\"350\" srcset=\"https:\/\/www.starlanguageblog.com\/wp-content\/uploads\/2023\/05\/pexels-cottonbro-studio-5184961.webp 640w, https:\/\/www.starlanguageblog.com\/wp-content\/uploads\/2023\/05\/pexels-cottonbro-studio-5184961-300x164.webp 300w\" sizes=\"(max-width: 640px) 100vw, 640px\" \/><\/span><\/h2>\n<p><span style=\"font-weight: 400;\">Sometimes, an exponential equation may have the same base on both sides. For example, 5 x 53 has the same base five on both sides. Sometimes, though the exponents on both sides are not the same, they can be made the same. For example, 5x = 125. Though it doesn&#8217;t have the same bases on both sides of the equation, they can be made the same by writing it as 5x = 53 (as 125 = 53). To solve the power equations in each of these cases, we just apply the property of equality of power equations, using which we set the exponents to be the same and solve for the variable.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Here is another example where the bases are not the same but can be made to be the same.<\/span><\/p>\n<h3><b>Example: Solve the exponential equation 7y + 1 = 343y<\/b><\/h3>\n<h3><b>Solution<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">We know that 343 is 73. Using this, the given equation can be written as,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">7y + 1 = (73)y<\/span><\/p>\n<p><span style=\"font-weight: 400;\">7y + 1 = 73y<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Now the bases on both sides are the same. So we can set the exponents to be the same.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">y + 1 = 3y<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Subtracting y from both sides,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">2y = 1<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Dividing both sides by 2,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">y = \u00bd<\/span><\/p>\n<h3><b>Example<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">Solve the equation 3x3x = 81.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">In this example, we have the base three raised to the power of the variable x, and the equation is set equal to 81. Our goal is to determine the value of x that satisfies the equation.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">To solve this equation, we can use the property of logarithms, which states that if ax = b, then loga(b) = x. Applying this property, we can take the logarithm of both sides of the equation with the base 3:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">log3(3x) = log3(81).<\/span><\/p>\n<p><span style=\"font-weight: 400;\">By using the property mentioned above, the equation simplifies to:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">x = log\u2083(81).<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Now, we need to evaluate the logarithm of 81 with base 3. The logarithm represents the exponent to which the base must be raised to obtain the argument. In this case, we want to find the exponent to which three must be raised to obtain 81. Evaluating this logarithm yields:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">x = log\u2083(81) = 4.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Therefore, the solution to the equation 3x = 81 is x = 4. By substituting x = 4 back into the original equation, we can verify that 34 equals 81.<\/span><\/p>\n<h2><span style=\"font-weight: 400;\">Solving Power Equations With Different Bases<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-17288\" src=\"https:\/\/wordpress-1162154-4054340.cloudwaysapps.com\/wp-content\/uploads\/2023\/05\/pexels-monstera-6238030-1.webp\" alt=\"Solving Power Equations With Different Bases\" width=\"640\" height=\"350\" \/><\/span><\/h2>\n<p><span style=\"font-weight: 400;\">Sometimes, the bases on both sides of an exponential <a href=\"https:\/\/starlanguageblog.com\/factoring-trinomials-of-the-form-x2-bx-c-worksheet\/\">equation<\/a> may not be the same or\u00a0 cannot be made the same. We solve the power equations using logarithms when the bases differ. For example, 5x = 3, which neither has the same bases on both sides nor can the bases be made the same. In such cases, we can do one of the following things:<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Convert the exponential equation into the logarithmic form using the formula bx = a \u21d4 log ba = x and solve for the variable.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Apply logarithm (log) on both sides of the equation and solve for the variable. In this case, we must use a logarithm property, log am = m log a.<\/span><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">We will solve the equation 5x = 3 in each of these methods.<\/span><\/p>\n<h3><b>Method 1<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">We will convert 5 x 3 into logarithmic form. Then we get,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">log53 = x<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Using the change of base property,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">x = (log 3) \/ (log 5)<\/span><\/p>\n<h3><b>Method 2<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">We will apply the log on both sides of 5x = 3. Then we get log 5 x log 3. Using the property log am = m log an on the left side of the equation, we get x log 5 = log 3. Dividing both sides by log 5,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">x = (log 3) \/ (log 5)<\/span><\/p>\n<h3><b>Important Notes on Power Equations<\/b><\/h3>\n<p><span style=\"font-weight: 400;\">Here are some important notes concerning the power equations:<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">To solve the power equations of the same bases, just set the exponents equal.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Applying a logarithm on both sides to solve the power equations of different bases.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The power equations with the same bases also can be solved using logarithms.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">If an exponential equation has one on any one side, then we can write it as 1 = a0 for any &#8216;a. For example, to solve 5x = 1, we can write it as 5x = 50, then we get x = 0.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">To solve an exponential equation using logarithms, we can apply &#8220;log&#8221; or &#8220;ln&#8221; on both sides.<\/span><\/li>\n<\/ul>\n<h2>FAQ&#8217;s<\/h2>\n<h3>What is a trinomial of the form x^2 + bx + c?<\/h3>\n<p>A trinomial of the form x^2 + bx + c is a quadratic expression with three terms, where the coefficient of the x^2 term is 1.<\/p>\n<h3>How do I factor a trinomial of the form x^2 + bx + c?<\/h3>\n<p>To factor a trinomial of the form x^2 + bx + c, you need to find two binomial factors that, when multiplied together, give you the original trinomial.<\/p>\n<h3>Can all trinomials of the form x^2 + bx + c be factored?<\/h3>\n<p>Not all trinomials of the form x^2 + bx + c can be factored. Some trinomials may be prime and cannot be factored into binomial factors.<\/p>\n<h3>What is the method for factoring trinomials of the form x^2 + bx + c?<\/h3>\n<p>The most common method for factoring trinomials of the form x^2 + bx + c is the &#8220;AC method&#8221; or &#8220;splitting the middle term.&#8221; This method involves finding two numbers whose product is equal to the product of the coefficient of x^2 and the constant term (c), and whose sum is equal to the coefficient of x (b).<\/p>\n<h3>Are there any special cases when factoring trinomials of the form x^2 + bx + c?<\/h3>\n<p>Yes, there are special cases. If the trinomial is a perfect square trinomial, it can be factored into the square of a binomial. Additionally, if the trinomial is a difference of squares, it can be factored using the difference of squares formula.<\/p>\n<h3>Can you provide an example of factoring a trinomial of the form x^2 + bx + c?<\/h3>\n<p>Sure! Let&#8217;s consider the trinomial x^2 + 7x + 10. To factor this trinomial, we need to find two numbers whose product is 10 and whose sum is 7. The numbers are 2 and 5. So, the factored form of the trinomial is (x + 2)(x + 5).<\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Solving Power Equations We must separate the exponentiating variable to solve exponential functions. With &#8220;a&#8221; as the base and &#8220;x&#8221; as the exponent, exponential functions have the general form f(x) = axe. The objective is to identify the value of &#8220;x&#8221; that resolves the inequality or equation. There are various options depending on the precise [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":17287,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2078],"tags":[3931],"class_list":["post-16982","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-maths","tag-solving-power-equations"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v23.8 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Solving Power Equations<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.starlanguageblog.com\/solving-power-equations\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Solving Power Equations\" \/>\n<meta property=\"og:description\" content=\"Solving Power Equations We must separate the exponentiating variable to solve exponential functions. With &#8220;a&#8221; as the base and &#8220;x&#8221; as the exponent, exponential functions have the general form f(x) = axe. The objective is to identify the value of &#8220;x&#8221; that resolves the inequality or equation. 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